(6k^2+2k+9)+(4k^2-5k)=0

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Solution for (6k^2+2k+9)+(4k^2-5k)=0 equation: 



(6k^2+2k+9)+(4k^2-5k)=0

We get rid of parentheses

6k^2+4k^2+2k-5k+9=0

We add all the numbers together, and all the variables

10k^2-3k+9=0

a = 10; b = -3; c = +9;
Δ = b2-4ac
Δ = -32-4·10·9
Δ = -351
Delta is less than zero, so there is no solution for the equation

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